Question

b 3^2-n-3 = 27/7 : 9^2
c 5^3•n+1=25^11
d 7^2•n+1÷7^4=49^2^3
e 10^2•n+1÷5^2•n+1=8^9


Va rog.Urgent.Dau coroana​

Answer 1

Verifica daca asa sunt scrise subpunctele

Answer 2

Explicație pas cu pas:

c.

${5}^{3n + 1} = {25}^{11} \iff {5}^{3n + 1} = {( {5}^{2} )}^{11} \\ {5}^{3n + 1} = {5}^{22} \iff 3n + 1 = 22 \\ 3n = 21 \implies n = 7$

d.

${7}^{2n + 1} \div {7}^{4} = {49}^{ {2}^{3} } \iff {7}^{2n + 1 - 4} = {( {7}^{2} )}^{8} \\ {7}^{2n - 3} = {7}^{16} \iff 2n - 3 = 16 \\ 2n = 19 \implies n = \frac{19}{2}$

e.

${10}^{2n + 1} \div {5}^{2n + 1} = {8}^{9} \\ {(10 \div 5)}^{2n + 1} = {( {2}^{3} )}^{9} \\ {2}^{2n + 1} = {2}^{27}\iff 2n + 1 = 27 \\ 2n = 26 \implies n = 13$