Question

b=[(-3)×(-3)^2÷(-3)^3×(-3)^4×(-3)^5÷(-3)^6×(3)7]^3

Answer 1

Tebuie sa stii regulile de la puteri:

$(a b)^{m} = a^m b^m\\(\frac{a}{b})^m = \frac{a^m}{b^m} \\a^{m + n} = a^m a^n\\a^{m - n} = \frac{a^m}{a^n} \\ (a^m)^n = a^{m n}$

Toate puterile pe care la ai sint in baza (-3)

Astfel ai:

$b = ((-3)^{1 + 2 - 3 + 4 + 5 - 6 + 7})^3 = ((-3)^{10})^3 = (-3)^{30}$