Question

B)3, (3)x+3,5=x=>x=
C) x/3+1/2=x/2+/3=>x=

Answer 1

b)3,(3)=(33-3)/9=30/9=10/3
3,5=35/10=7/2
10/3x+7/2=x amplificam pe x cu 3
10/3x-3x/3= -7/2
7/3x= -7/2
x= -7/2×3/7
x= -3/2

c) amplificam pe x/3 cu 2,pe 1/2 cu 3,pe x/2 cu 3 si e 1/3 cu 2
2x+3=3x+2
2x-3x=2-3
-x= -1
x=1