Question

b=3^46:(9^22+3^20x27^8+9^30:81^4)-2^23:(2^22+2^22) pls

Answer 1

b=3^46:(9^22+3^20x27^8+9^30:81^4)-2^23:(2^22+2^22)

b = 3^46:(3^44+3^20×3^24+3^60:3^16)-2^23:2×2^22

b = 3^46:(3^44+3^44+3^44) - 2×2^1

b = 3^46 : 3 × 3^44 - 4

b = 3 × 3^2 - 4

b = 3 × 9 - 4

b = 27 - 4

b = 23