Question

b) [(3.X – 12): 6 + 7]:10 – 2 = 0​

Answer 1

$[(3x-12):6+7):10-2=0\\(\frac{3x-12}{6}+7)*\frac{1}{10}-2=0$

$[\frac{3(x-4)}{6}+7]*\frac{1}{10} -2=0\\(\frac{x-4}{2}+7)*\frac{1}{10}-2=0\\\frac{x-4+14}{2} *\frac{1}{10}-2=0\\\frac{x+10}{2} *\frac{1}{10}-2=0\\x+10-40=0\\x=30=0|+30\\=>x=30$