Question

b. (32×15-32×5)+11×12+7×{124-5×[21 -2×(23×17–24×12)]};​

Answer 1

.........................................

(32×15-32×5)+11×12+7×{124-5×[21 -2×(23×17–24×12)]};​

480 - 160 + 132 + 7 x { 124 - 5 x[ 21 - 2 x ( 391-288}])

452 + 7 x { 124 - 5 x [ 21 - 2 x 103]}

452 + 7 x { 124 - 5 x [ 21 - 206] }

452 + 7 x { 124 - 5 x( -185)}=

452 + 7 x [ 124 + 925] =

452 + 7 x 1049 = 7343 + 452 = 7795 ;

R:7795

Answer 2

Salutare!

(32×15-32×5)+11×12+7×{124-5×[21-2×(23×17–24×12)]}=

(480-160)+132+7×{124-5×[21-2×(391-288)]}=

320+132+7×[124-5×(21-2×103)]=

320+132+7×[124-5×(21-206)]=

320+132+7×(124-5×(-185))=

320+132+7×(124+925)=

320+132+7×1049=

320+132+7343=

452+7343=

7795