Question

b) {3³+[3²+(13²-5²×5)÷2²]÷2²}2¹ =
aratați ca nr a=2018¹+2×(1+2+3...+2017)este patrat perfect
calculati
b= 11¹²÷11⁸+5³-4⁴×4⁸)÷[(11²)²+5³-(4⁴)³]=​

Answer 1

Răspuns:

b) {27+[9+(169-125)÷4]÷4}×2= {27+[(9+44)÷4]÷4}×2= [27+(9+11)÷4]×2= ( 27 +20÷4)×2= (27+5)×2= 64

a= 2018+2×(1+2+3+...+2017)= 2018+2×(2017×2018/2)= 2018+2×(2017× 1009)= 2018+2×(2 035 153)= 2018+4.070.306= 4 072 324 =》 2018² este patrat perfect

b= (11¹²÷11⁸+5³-4⁴×4⁸)÷ [(11²)²+5³-(4⁴)³] = (11⁴+5³-4¹²)÷(11⁴+5³-4¹²)= 1