Question

b) 40 6-4x[3x(30-18:6:3)]; c) 832:8+[40+8x(100:5-72:4)]x10; d) 25+6x[107-100:(8-3)]9x1; e)1+3x[7+8x7-3+3x(5+6)]; f) [55x5-(199-99x2+20x5)+220:10]:4;

Answer 1

c) 832:8+[40+8x (100:5-72:4)]x10=
=832:8+[40+8x(20-18)]x10=
= 832:8+(40+8x2)x10=
=832:8+(40+16)x10=
=832:8+56x10=
= 104+560=
=664

e) 1+3x [7+8x7-3+3x (5+6)]=
= 1+3x (7+8x7-3+3x11)=
=1+3×(7+56-33)=
=1+3×30=
=1+90=
=100

f) [55×5-(199-99×2+20×5)+220:10]:4
= [55×5-(199-198+100)+220:10]:4=
=(55×5-101+220:10):4=
=(275-101+22):4=
=(275-123):4=
=152:4=
=38



scuze că nu le-am făcut restul dar lipsea câte ceva. o adunare, înmulțire..