Question

b)5radical din12×(radical din 2-radical din 6)-radical din 16-3×2+10 radical din3.​

Answer 1

√16=4

√12=2√3

5×2√3×(√2-√6)-4-6+10√3=

10√3×√2-10√3×√6-10+10√3=

10√6-10√18-10+10√3=

10√6-10×3√3+10√3=

10√6-30√3+10√3=10√6-20√3=10(√6+2√3)