Question

b) c-324 = 528;
d) 2x - 15 = 17;
f) 3.X + 16 = 37;
h) 132 : (3.z) = 11;
j) [(x:9).10].7 = 140;
1) (y : 4-59): 3 - 192 : 2 = 50.​

Answer 1

Răspuns:

c= 528-324 c= 204

2x-15=17 2x=17-(-15) 2x=32 x=16

3x+16=37 3x=37-16 3x=21 x=7

132:3z=11 3z=132•11 3z=1452 z=484

[(x:9)•10]=20 x:9=2 x=18

(y:4-59):3-96=50 (y:4-59):3=146

y:4-59=438 y:4=497 y=1988