Question

b, c si d
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Answer 1

b) = ($\frac{-2+3}{36} * (-\frac{5}{6}) =  \frac{1}{36} * (-\frac{5}{6}  = -\frac{1*5}{36*6} = \frac{5}{216}$

c)=$(\frac{-7+33}{39}) * ( \frac{-3}{2}) = \frac{26}{39}  *  ( \frac{-3}{2}) = -\frac{26*3}{39*2} =-\frac{78}{78} =-1$

d) = $\frac{-6+16}{84} * \frac{11}{5} = \frac{10}{84}  * \frac{11}{5} = \frac{10*11}{84*5} = \frac{110}{420} =  \frac{11}{42}$