Question

b) Ordonează crescător numerele : 11 supra 3; 3,(3); si 3 la puterea 5 supra 6​

Answer 1

$3.(3) = 3 \frac{3}{9} = \frac{3 \times 9 + 3}{9} = \frac{30}{9} = \frac{10}{3} = \frac{20}{6}$

$\frac{ {3}^{5} }{6} > \frac{22}{6} > \frac{20}{6}$

$\frac{11}{3} = \frac{22}{6}$

Ordinea: 3,(3),11 supra 3; 3 la puterea 5 supra 6

Answer 2

$\frac{11}{3}\approx3,(6); \\ 3^{\frac{5}{6}}=\sqrt[6]{3^5}=\sqrt[6]{243}\approx2,5 \\ \Rightarrow \boxed{3^{\frac{5}{6}}; \ 3,(3); \ \frac{11}{3}}$