Question

B si c, va rog mult... ​

Answer 1

$\frac{8+15x-2x^{2}}{3+5x-2x^{2}}=\frac{-2x^{2}+16x-x+8}{-2x^{2}+6x-x+3}=\frac{-2x(x-8)-(x-8)}{-2x(x-3)-(x-3)}=\frac{(x-8)(2x+1)}{(x-3)(2x+1)}=\frac{x-8}{x-3}$

x - 3 ≠ 0 => x ≠ 3 ⇒ x ∈ R - {3}

$\frac{6x^{2}+43x+7}{18x^{2}-9x-2}=\frac{6x^{2}+42x+x+7}{18x^{2}+3x-12x-2}=\frac{6x(x+7)+(x+7)}{3x(6x+1)-2(6x+1)}=\frac{(6x+1)(x+7)}{(6x+1)(3x-2)}=\frac{x+7}{3x-2}$

3x-2 ≠ 0 => 3x ≠ 2 => x ≠ 2/3 ⇒ x ∈ R - (2/3)