Question

B si D VA ROG, URGENT, DAU COROANA. ​

Answer 1

Răspuns:

b)

$=\sqrt{4*6} (\frac{7\sqrt{3} -5\sqrt{2} }{\sqrt{6}} )-3\sqrt{6}(\frac{6\sqrt{3} -5\sqrt{2} }{\sqrt{6}} )-\sqrt{25*2} =$

$=2\sqrt{6}*\frac{7\sqrt{3} -5\sqrt{2} }{\sqrt{6}} -3\sqrt{6}*\frac{6\sqrt{3} -5\sqrt{2} }{\sqrt{6}} -5\sqrt{2}=$

$=2(7\sqrt{3} -5\sqrt{2} ) -3(6\sqrt{3} -5\sqrt{2} }) -5\sqrt{2}=$

$=14\sqrt{3} -10\sqrt{2} -18\sqrt{3} +15\sqrt{2} } -5\sqrt{2}=$

$=-4\sqrt{3}$

d)

$=\sqrt{35} *\frac{8\sqrt{7}-4\sqrt{5} }{\sqrt{35} }- \sqrt{4*35} *\frac{6\sqrt{7}-9\sqrt{5} }{\sqrt{35} } +\sqrt{4*49*5} =$

$=8\sqrt{7}-4\sqrt{5} - 2*(6\sqrt{7}-9\sqrt{5} ) +14\sqrt{5} =$

$=8\sqrt{7}-4\sqrt{5} - 12\sqrt{7}+18\sqrt{5} +14\sqrt{5} =$

$=28\sqrt{5}-4\sqrt{7}$

Explicație pas cu pas: