Question

b) Suma a 10 numere naturale inpare distincte este 100. Aflați numerele​

Answer 1

Răspuns:

Explicație pas cu pas:

(n+1)+(n+3)+(n+5)+(n+7)+(n+9)+(n+11)+(n+13)+(n+15)+(n+17)+(n+19)=100

10n+(1+3+5+7+9+11+13+15+17+19)=100

10n = 100-(1+3+5+7+9+11+13+15+17+19)

10n = 100-100  deci  n = 0

Atunci numerele vor fi

(n+1)+(n+3)+(n+5)+(n+7)+(n+9)+(n+11)+(n+13)+(n+15)+(n+17)+(n+19)

atunci numerele vor fi :

(n+1)=0+1=1

(n+3)=0+3=3

(n+5)=0+5=5

(n+7)=0+7=7

(n+9)=0+9=9

(n+11)=0+11=11

(n+13)=0+13=13

(n+15)=0+15=15

(n+17)=0+17=17

(n+19)=0+19=19

1, 3, 5, 7, 9, 11, 13, 15, 17, 19