Question

b=$10^{3}$:{123+34:[(2x$3^{2}$)$^{2}$:18-$17^{0}$x$1^{25}$}
b=??

Answer 1

1000:{123+34:[(2x9)^2:18-1x1}=
=1000:[123+34:(18-1)]=
=1000:(123+34:17)=
=1000:(123+2)=
=1000:125=
=8

Answer 2

[tex]10^3:[123+34:(18^2:18-1\cdot1)]=\\ =1000:[123+34:(18-1)]=\\ =1000:(123+2)=\\ =1000:125= \\=8[/tex]