Question

b) x²+2x+1-x^4
Dau coroană​

Answer 1

$\boxed{(a\pm b)^2=a^2\pm2ab+b^2}\\\boxed{a^2-b^2=(a+b)(a-b)}\\x^2+2x+1-x^4=(x+1)^2-x^4=(x+1)^2-(x^2)^2=(x+1+x^2)(x+1-x^2)$