Question

Buna!Am nevoie urgent de ajutor..Maine am matematica si ma asculta ajutati-ma la acest exercitiu daca stiti! :(

Rezolvati in R:

a)√2 x+1=x+√2

b)x√5-3√5=2√5x-√5

c)√3(x-2)-2√2x=2(√3x-√2x-3)

d)√5(x-2)-30=20-√20(2x-3)

e)(√2+1)(x+1)-2√2(x+2)+(√2+1)totul la puterea a doua +1=4

Answer 1

la acest tip de exercitii se trec termenii cu x in stanga egalului si cei fara x in dreapta.can treci un membru dintr-o parte in alta a semnului = se schimba semnul
a) √2x+1=x+√2
x(√2-1)=√2-1
x=(√2-1)/(√2-10=1
b)
x√5-3√5=2x√5-√5
x√5-2x√5=3√5-√5
-x√5=2√5
x=-2√5/√5=-2
c)
x√3-2√3-2x√2=2x√3-2x√2-6
x√3-2x√2-2x√3+2x√2=2√3-6
-x√3=2√3-6
x=(6-2√3)/√3
se rationalizeaza
x=(6√3-6)/3=2√3-2
d)
x√5-2√5-30=20-4x√5+6√5
x√5+4x√5=50+8√5
5x√5=50+8√5
x=(50+8√5)/5√5
x=(10√5+8)/5

e)x√2+x+√2+1-2x√2-4√2+3+2√2+1=4
-x√2+x-√2+5=4
x(1-√2)=-(1-√2)
x=(1-√2)/-(1-√2)=-1