Question

Buna!As vrea sa stiu cum se rezolva 2,3,4! Multumesc!

Answer 1

ex.2 rezulta
18/3√3(8/√3-√(27/4))+(-2√2)/2:√3/9= simplificam ce se poate
=6/√3(8/√3-3√3/2)-√2:√3/3=
=48/3-54/2-√2x3/√3=
=16-27-3√2/√3=
=-11-3√6/3=-11-√6

ex.3
a) =4x²+12x+9-25=
4x²+12x-16=0       
4(x²+3x-4)=0
x²+3x-4=0
Δ=9+16=25
x1=(-3+5)/2=1
x2=(-3-5)/2=-8/2=-4
deci (2x+3)²-25=(x-1)(x+4)

b)=x²(x+3)-4(x+3)=
=(x+3)(x²-4)= (x+3)(x+2)(x-2)

c) 9x²-24x+16=0
Δ=576-576=0
x1=x2=24/18=4/3
9x²-24x+16=(x-4/3)²=(3x-4)²

ex.4
x²-2x-15=0
Δ=4+60=64
x1=(2-8)/2=-6/2=-3
x2=(2+8)/2=10/2=5
x²-2x-5=(x+3)(x-5)

x²-10x+25=0
Δ=100-100=0
x1=x2=10/2=5
x²-10+25=(x-5)²

deci (x²-2x-15)/(x²-10x+25)=(x+3)(x-5)/(x-5)² simplif cux-5
=(x+3)/(x-5)

Answer 2

4) x²-2x-15
    x²-10x+25
1-x-3
1-5x+5
x-3+
1+5-5x
x-2
6-5x
-2
1
-2
1