Question

Buna!Cum se rezolva 7x+21 supra x+2=x+3 supra 5?

Answer 1

7x+21 supra x+2 = x+3 supra 5
=> 5(7x+21) = (x+3)(x+2)
=> 5 * 7(x+3) = (x+3)(x+2)
(x+3 cu x+3 se simplifica) => 35 = x+2
=> x = 33

Answer 2

$\frac{7x+21}{x+2} = \frac{x+3}{5} => 5(7x+21)=(x+3)(x+2)$
Dand factor comun pe 7 in prima parte , se poate reduce x+3
si va ramane : 35=x+2 => x=33