Question

Bună ,daca macputeti ajuta cu acest exercitiu va rog ?
Dau coroana si Stelute
Multumesc!
13 : Efectuati (exercitiul a nu il faceti decat restul imi trebuie multumesc de ajutor)​

Answer 1

$-\frac{3}{55} : \frac{9}{10} - (-\frac{5}{22} ) . \frac{4}{5} =$ $-\frac{3}{55} . \frac{10}{9} +\frac{2}{11} =$ $-\frac{2}{33} + \frac{2}{11} =$$-\frac{2}{33}+\frac{6}{33} =$$\frac{4}{33}$

$(-\frac{9}{10}) : (+\frac{18}{25} )- (+\frac{3}{5} ):\frac{21}{20} =$$\frac{9}{10} . \frac{25}{8} - \frac{3}{5} . \frac{20}{21} =$$\frac{5}{4} - \frac{4}{7} =$$\frac{35-16}{28} = \frac{19}{28}$

$\frac{13*3+1}{13} : (-\frac{32}{26} ) - (-\frac{3}{6} ) =$$\frac{40}{13} . \frac{13}{16} + \frac{1}{2} =$ $\frac{5}{2} + \frac{1}{2} = \frac{6}{2} = 3$

$\frac{2*55+15}{55}: (-\frac{6*4+1} {4} ) -(-\frac{15}{18} ) : \frac{3*1+2}{3} =$$\frac{125}{55} . (-\frac{4}{25} ) - (-\frac{15}{18}). \frac{3}{5} =$$-\frac{4}{11} + \frac{1}{2} = \frac{-8+11}{22} = \frac{3}{22}$

$-\frac{7}{54} . (- \frac{18}{21}) - (-\frac{4}{63}) . \frac{28}{1}=$$\frac{1}{9} + \frac{16}{9} = \frac{17}{9}$

$(-\frac{9}{84}) . \frac{3*9+1}{9} - (-\frac{5}{12} ) . \frac{15*1+7}{15} =$$-\frac{9}{84} . \frac{28}{9} + \frac{5}{12} . \frac{22}{15} =$$-\frac{28}{81} + \frac{11}{18} = \frac{-28*2+9*11}{162} =\frac{-56+99}{162}= \frac{43}{162}$

$\frac{-2*6-5*5}{210} : (-\frac{3*10+7}{10} ) + \frac{3}{7} . \frac{5}{18} =$$\frac{-12-25}{210} . \frac{10}{37} + \frac{5}{42} =$$\frac{-37}{210} . \frac{10}{37} + \frac{5}{12} =$$\frac{-1}{21} + \frac{5}{12} = \frac{-1*4+5*7}{84} =$$\frac{31}{84}$