Question

Buna ,imi rezorvati si mie aceste exercitiu ?! Daca se paote + explicatie
2√3-√2 supra √3 + 3√2 + √3 supra √2  -  1 supra √6

Answer 1

$\frac{2\sqrt{3}-\sqrt{2}}{\sqrt{3}}+\frac{3\sqrt{2} + \sqrt{3}}{\sqrt{2}}-\frac{1} {\sqrt{6}}$=

=$\frac{2\sqrt{3}}{\sqrt{3}}- \frac{\sqrt{2}}{\sqrt{3}}+\frac{3\sqrt{2}}{\sqrt{2}}+\frac{\sqrt{3}}{\sqrt{2}}-\frac{1} {\sqrt{6}}$=

=$2- \frac{2}{\sqrt{6}}+3+\frac{3}{\sqrt{6}}-\frac{1} {\sqrt{6}}$=

=2+3=5