Question

Buna,ma poate ajuta și pe mine cineva cu astea, multumesc.
$b)3 {}^{5} \div (3 {}^{2} \div 3 {}^{7} ) {}^{3} \div 3 {}^{2} {}^{ {}^{5} }$
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Answer 1

Răspuns:

a)

$(56:2^2+2*9:3):2^2-2^2=(56:4+18:3):4-4=(14+6):4-4=20:4-4=5-4=1$

c)

$(576:48+4^2):(2^9:2^7)=(12+16):2^{9-7}=28:2^2=28:4=7$

d)

$[(25*7-13^2)*12-8^2]*2^{17}-4^{10}=[(175-169)*12-64]*2^{17}-4^{10}=(6*12-64)*2^{17}-4^{10}=(72-64)*2^{17}-4^{10}=8*2^{17}-4^{10}=2^3*2^{17}-2^{2*10}=2^{20}-2^{20}=0$

b)

$3^5:(3^2:3^7)^3:3^{(2)^5}=3^5:3^{2-7}:3^{2*5}=3^5:3^{-5}:3^{10}=\frac{3^5}{\frac{1}{3^5}}:3^{10}=3^5*3^5:3^{10}=3^{10}:3^{10}=1$

Explicație pas cu pas: