Question

Buna ma puteti ajuta cu aceasta problema este pentru nota,chiar am nevoie,multumesc

Answer 1

Se da:
E=24V
r=0,5ohm
R1=10ohm
R2=30ohm
a)K-deschis, I1=?A
b)K-inchis, Lac=0,6Lab, Re=?ohm
c)Lac=Lac, I=?A
d)U2=?V

Formule:
a)Pt K-deschis:
I=I1

I=E/(R1+r)

I1=E/(R1+r)

b)Pt K-inchis si Lac=0,6Lab:
1/Re=(1/R1)+(1/R2')

R2'=0,6R2

1/Re=(1/R1)+(1/0,6R2)
1/Re=(R1+0,6R2)/(0,6R1R2)
Re=0,6R1R2/(R1+0,6R2)

c)Pt K-inchis si Lac=Lab:
I=E/(Re+r)

1/Re=(1/R1)+(1/R2)
1/Re=(R1+R2)/(R1R2)
Re=R1R2/(R1+R2)

d)Uab=U

U=E-Ir

Uab=E-Ir

Calcule:
a)I1=24/(10+0,5)=2,285A
b)Re=0,6*10*30/(10+0,6*30)=6,428ohm
c)Re=10*30/(10+30)=7,5ohm
I=24/(7,5+0,5)=3A
d)Uab=24-3*0,5=22,5V