Question

Bună!Ma puteti ajuta,va rog,cu problema 6?Dau coroana!​

Answer 1

Răspuns:

a=3^79-2×3^78-2×3^77-3^76

a=3^76(3^3-2×3^2-2×3^1-1)

a=3^76(27-2×9-2×3-1)

a=3^76(27-18-6-1)

a=3^76×2

b=2^100-2^99-3×2^97-2^96

b=2^96(2^4-2^3-3×2^1-1)

b=2^96(16-8-6-1)

b=2^96×1=2^96

Answer 2

Răspuns:

Explicație pas cu pas:

a = 3^79 - 2*3^78 - 2*3^77 - 3^76 = 3^76*(3^3 - 2*3^2 - 2*3 - 1)

= 3^76*(27 - 2*9 - 6 - 1) = 2*3^76

b = 2^100 - 2^99 - 3*2^97 - 2^96 = 2^96*(2^4 - 2^3 - 3*2 - 1)

= 2^96*(16 - 8 - 6 - 1) = 2^96

__________

a = 2*3^76 = 2*(3^2)^38 = 2*9^38

b = 2^98 = (2^3)^32 = 8^32

a > b