Question

Buna seara as dori sa stiu cat face: f'(x) avand in vede ca f(x) este ln x/x^2. x apartine (0, +infinit)

Answer 1

$f(x)= \frac{lnx}{ x^{2} } ;f'(x)= \frac{(lnx)'* x^{2} -lnx*( x^{2} )'}{( x^{2} )^2}= \frac{ \frac{1}{x}* x^{2} -lnx*2x }{x^4}= \frac{x(1-2lnx)}{x^4}= \\ = \frac{1-2lnx}{x^3}$