Question

Buna va rog frumos sa ma ajutati cu acest exercitiu!!! urgent ​(dati pe poza full)

Answer 1

Răspuns:

Explicație pas cu pas:

c) {2:[(12/36-1/12-1/9)·3 3/5]+0,(3)·3 1/3}-4 1/10=

{2:[(4/12-1/12-1/9)·18/5]+3/9·10/3}-41/10=

{2:[(3/12-1/9)·18/5]+(3·10)/(9·3)}-41/10={2:[(9-4)/36)·18/5]+10/9}-41/10=

{2:[(5/36)·(18/5)]+10/9}-41/10={2:[(5·18)/(36·5)]+10/9}-41/10={2:1/2+10/9}-41/10= {2·(2/1)+10/9}-41/10=4+10/9-41/10=(4·9+10)/9-41/10= 46/9-41/10=(46·10-41·9)/90=(460-369)/90= 91/90= 1 1/90

d) [0,4-1 2/15:2 2/3+2 11/20·3 9/17·0,(5)]:1/5=

[4/10-17/15:8/3+51/20·60/17·5/9]:1/5=

[2/5-(17/15)·(3/8)+(51·60·5)/(20·17·9)]:1/5=

[2/5-(17·3)/(15·8)+(3·60·5)/(20·9)]:1/5=

[2/5-17/(5·8)+(3·5)/9]:1/5=[(2·8-17)/40+5/3]:1/5=[-1/40+5/3]:1/5=

[(-3+40·5)/120 ]:1/5=    (197/120)·(5/1)=(197·5)/120=197/24 = 8 5/24    

e) [(-5/8+7/9-3/4):(-1/12)+0,1(2):1,1]:(-3 1/9)=

[(-5/8-6/8+7/9):(-1/12)+11/90:11/10]:(-28/9)=

[(-11/8+7/9):(-1/12)+(11/90)·(10/11)]:(-28/9)=

[(-11·9+7·8)/72·(-12/1)+(11·10)/(90·11)]·(-9/28)=

[(-99+56)/72·(-12)+10/90]·(-9/28)=[(-43/72)·(-12)+1/9]·(-9/28)=(43/6+1/9)·(-9/28)=[(43·3+2)/18·(-9/28)=131/18·(-9/28)=131·(-9)/(18·28)= -131/56=-2 19/56