Question

Buna! Va rog mult ajutati-ma!

Answer 1

iata raspunsul la prima problema

Answer 2

(x²-2x-8)/(x²-3x-10)=
=(x²+2x-4x-8)/(x²-5x+2x-10)=
=[x(x+2)-4(x+2)]/[x(x-5)+2(x-5)]=
=(x+2)(x-4)/(x-5)(x+2)=
=(x-4)/(x-5)

5x/(x+2) - 2x/(x-1)=
=(5x²-5x-2x²-4x)/(x+2)(x-1)=
=(3x²-9x)/(x+2)(x-1)=
=3(x²-3)/(x+2)(x-1)

(2x-1)/(x+3)-(-2x)/(x-2)=
=(2x-1)/(x+3)+2x/(x-2)=
=(2x²-x-4x+2+2x²+6x)/(x+3)(x-2)=
=(4x²+x+2)/(x+3)(x-2)=

3/(x²-1)-2x/(x²+2x+1)=
=3/(x+1)(x-1)-2x/(x+1)²=
=[3(x+1)-2x(x-1)]/(x-1)(x+1)²=
=(3x+3-2x²+2x)/(x-1)(x+1)²=
=(3+5x-2x²)/(x-1)(x+1)²