Question

Buna! Va rogg ajutati-ma rapiddd ​

Answer 1

Răspuns:

b) Denis

Explicație pas cu pas:

$3 - 2 \sqrt{3} = \sqrt{9} - \sqrt{12} < 0 \\ \implies |3 - 2 \sqrt{3} | = 2 \sqrt{3} - 3$

$a = \frac{6}{ \sqrt{3} } - |3 - 2 \sqrt{3} | = \frac{6 \sqrt{3} }{3} - (2 \sqrt{3} - 3) = 2 \sqrt{3} - 2 \sqrt{3} + 3 = 3$

$5 - 4 \sqrt{2} = \sqrt{25} - \sqrt{32} < 0 \\ \implies |5 - 4 \sqrt{2} | = 4 \sqrt{2} - 5$

$b = \frac{8}{ \sqrt{2} } - |5 - 4 \sqrt{2} | + | - 7| = \frac{8 \sqrt{2} }{2} - (4 \sqrt{2} - 5) + 7 = 4 \sqrt{2} - 4 \sqrt{2} + 5 + 7 = 12$

=>

$m_{g} = \sqrt{ab} = \sqrt{3 \cdot 12} = \sqrt{36} = \bf 6$