Question

Buna ziua
ma puteti ajuta?
a+b=24
axb=143
sa se afle suma inverselor numerelor
multumesc

Answer 1

[tex]a+b=24=\ \textgreater \ a=24-b\\ a*b=143\\ (24-b)*b=143\\ 24b-b\²-143=0\\ b\²-24b+143=0\\ b\²-11b-13b+143=0\\ b(b-11)-13(b-11)=0\\ (b-11)(b-13)=0=\ \textgreater \ b_1=11,b_2=13\\ a)b=11=\ \textgreater \ a=13\\ \frac{1}{11}+\frac{1}{13}=\frac{24}{143}\\ b)b=13=\ \textgreater \ a=11\\ \frac{1}{13}+\frac{1}{11}=\frac{24}{143}[/tex]