Question

Bunica are o suma de bani, ce o imparte celor 3 nepoti ai ei. Primului nepot ii da 1/3 din suma plus 32 lei, celui de-al doilea nepot ii da 1/3 din ce a ramas plus 32 lei, iar celui de-al treilea ii da 1/3 din rest plus 32 lei. Ce suma avea bunica? Care este suma fiecarui nepot?

Answer 1

x=suma
x/3+32=nepot 1
x-x/3-32=2x/3-32=rest
(2x/3-32)×1/3+32=2x/9-32/3+32=2x/9+64/3=nepot 2
2x/3-32-2x/9-64/3=4x/9-160/3=rest
(4x/9-160/3)×1/3+32=4x/27-160/9+32=4x/27+128/9=nepot 3
x/3+32+2x/9+64/3+4x/27+128/9=x
9x+864+6x+576+4x+384=27x
19x+1824=27x
8x=1824
x=228 lei

228×1/3+32=76+32=108 lei nepot 1
228-108=120
120×1/3+32=40+32=72 lei nepot 2
120-72=48
48×1/3+32=16+32=48 lei nepot 3