Question

C=3+3 la 2+3 la 3+.....+3 la 3003+3 la 2004 aratati ca C e divizibil cu 4

Answer 1

C = 3(1 + 3) + 3³(1 + 3) + .. + 3³⁰⁰³(1 + 3)

C = 4×(3 + 3³ + ... + 3³⁰⁰³) DIVIZIBIL CU 4

Answer 2

C=3+3^2+3^3+...+3^2003+3^2004⋮4

C=3(1+3)+3^3(1+3)+...+3^2003(1+3)

C=3*4+3^3*4+...+3^2003*4

C=4(3+3^3+3^5+...+3^2001+3^2003)

=> C⋮4