Question

c) (3 la puterea 19 *25 la puterea 9 totul la puterea 2 / 15 la puterea 36

Answer 1

$(3^{19}*25^9)^2:15^{36}=$

$(3^{19})^2*[(5^2)^9]^2:(3*5)^{36}=$

$3^{38}*5^{36}:(3^{36}*5^{36)=$

$3^{38-36}*5^{36-36}=$

$3^2*1=$

$9$

Answer 2

[tex](3^{19}*25^{9})^2 :15^{36}=\\\\ =(3^{19}*5^{18})^2:(3^6 * 5^{36})\\\\ =(3^{38}*5^{36}):3^6 * 5^{36})\\\\ =3^2\\\\ =9. [/tex]