Question

c) (3la puterea7+2*3la puterea 7+2*3la puterea 8)/3la puterea8

(3
${ {3}^{7} + 2 \times {3}^{7 } + {3}^{8} } \div {3}^{8} =$
​

Answer 1

3^7+2*3^7+3^8/3^8=

(2+1)*3^7+3^(8-8)=

3*3^7+3^0=

3^(7+1)+1=

3^8+1=

6561+1=

=6562