Question

c) (6+12+18+24 + ... +600)la puterea 2 :(3+6+9+12+...+300):(1+2+3+...+100).

Answer 1

Răspuns:

Explicație pas cu pas:

c)

( 6 +12 + 18 + 24+ ...+ 600)²: ( 3 +6 + 9 + .... + 300) : ( 1 + 2 +3 + .... +100) =

= [ 6 x ( 1 + 2 + 3 + ..... + 100 )]² : 3 ×( 1 + 2 + ...+100) : (1+2+3+...+100) =

= 6² x ( 1+2+3+....+100)² : 3 × ( 1+2+3+....+100):(1+2+3+....+100) =

= (36 : 3 )x( 1+2+3+.....+100)⁽²⁻¹⁻¹⁾ =

= 12 x 1 =

= 12