Question

C alculati nr de moli continuing in 9,8g H2SO4

a)Cate grame de CaCO3 sunt c ontinute in 10 moli CaCO3?
b)Cate molecule sunt conntinute in 10 moli de CaCO3?

Answer 1

H2SO4

M=2+32+4.16=98-------->1mol=98g

1mol H2SO4------------98g H2SO4

X moli----------------------9,8 g

x=9,8:98=0,1 moli H2SO4

CaCO3

M=40+12+3.16=100------->1mol=100g

100g CaCO3-----------1molCaCO3

Xg--------------------------10 moli

x=100 . 10=1000 gCaCO3

CaCO3

M=100------->1mol=100 g      23

1mol CaCO3-----------6,023.10 molecule CaCO3

10 moli---------------------x

                           23

X=10 . 6,023.10       molecule CaCO3