Question

c) , d) și e) cu rezolvare.

Answer 1

Răspuns:

c)

$=(\frac{23*4+31*7}{63*4}-\frac{21*3+4*5}{4*21} )*48:(\frac{3}{5} *\frac{8}{7} )=$

$=(\frac{92+217-3*(63+20)}{4*63} )*48:\frac{24}{35}=$

$=(\frac{309-249)}{4*63} )*48*\frac{35}{24}=$

$=\frac{60}{4*63} *2*35=$

$=\frac{15}{7*9} *2*5*7=$

$=\frac{5}{3} *2*5=$

$=\frac{50}{3}$

d)

$=[(\frac{5*17+9*3}{120} -\frac{5*11+31*3}{240} ):\frac{19}{5} ]*\frac{12}{7} =$

$=[\frac{2*(85+27)-55-93}{240}*\frac{5}{19} ]*\frac{12}{7} =$

$=(\frac{224-148}{48}*\frac{1}{19} )*\frac{12}{7} =$

$=\frac{76}{48}*\frac{1}{19} *\frac{12}{7} =$

$=\frac{1}{7}$

e)

$=\frac{1}{2} +\frac{1}{2} :(\frac{2+3}{2} *8-\frac{1}{2} *4*8)=$

$=\frac{1}{2} +\frac{1}{2} :(5*4-2*8)=$

$=\frac{1}{2} +\frac{1}{2} :4=$

$=\frac{1}{2} +\frac{1}{2} *\frac{1}{4} =$

$=\frac{1}{2} +\frac{1}{8} =$

$=\frac{4+1}{8} =$

$=\frac{5}{8}$

Explicație pas cu pas: