Question

C1.
Se dă funcția f: R → R, f(x) = x + 3. Calculaţi:
f(2) + f (2^) + f (2la puterea 3) + ... + f(2la put 7).
Domonatnoti​

Answer 1

Răspuns:

275

Explicație pas cu pas:

f: R → R, f(x) = x + 3

f(2) = 2+3=5 =>f(2)=5

f(2²)=f(4)=4+3=7 =>f(2²)=7

f(2³)=f(8)=8+3=11 =>f(2³)=11

f(2⁴)=f(16)=16+3=19 =>f(2⁴)=19

f(2⁵)=f(32)=32+3=35 =>f(2⁵)=35

f(2⁶)=f(64)=64+3=67 =>f(2⁶)=67

f(2⁷)=f(128)=128+3=131 =>f(2⁷)=131

f(2) + f (2²) + f (2³) + ... + f(2⁷)=5+7+11+19+35+67+131=275