Question

caculeaza factorialul 6(2n)! supra (2n-1)!=n! supra (n-3)!

Answer 1

$\frac{6*(2n)!}{(2n-1)!} = \frac{n!}{(n-3)!}$ 
ecuatia are solutii daca n≥3
$\frac{6(2n-1)!*2n}{(2n-1)!} = \frac{(n-3)!(n-2)(n-1)n}{(n-3)!}$
$12n=(n-2)(n-1)n$
12=$n^{2}-3n+2$
$n^{2}-3n-10=0$
[tex]n=-2 n=5[/tex]
Raspuns:n=5