Question

Calcul de masa moleculara a substanțelor H3Po4,
Mg (OH)2,
CaCo3

Answer 1

M(H3Po4)=1*3+209*4=3+836=839g/mol
M(Mg (OH)2)=24+16*2+1*2=24+32+2=58g/mol
M(CaCo3)=41+59*3=41+177=218g/mol

Answer 2

MASA MOLECULARA NU ARE UNITATE DE MASURA. (Cea care se exprima in g/mol si este egala cu masa moleculara este MASA MOLARA)

$M_{H3PO4}=3*1+31+4*16=98$

$M_{Mg(OH)2}=24+2*16+2*1=58$

$M_{CaCO3}=40+12+3*16=100$