Question

Calculand 4√24(9 supra √18 - 4 supra√12)-5(√27-√32) este egal cu?

Answer 1

Răspuns:

$9 \sqrt{3} + 4 \sqrt{2}$

Explicație pas cu pas:

$4 \times 2 \sqrt{6} ( \frac{9}{3 \sqrt{2} } - \frac{4}{2 \sqrt{3} } ) - 5(3 \sqrt{3} - 4 \sqrt{2} )$

$8 \sqrt{6} ( \frac{3}{ \sqrt{2} } - \frac{2}{ \sqrt{3} } ) - 15 \sqrt{3} + 20 \sqrt{2}$

$8 \sqrt{6} ( \frac{3 \sqrt{2} }{2} - \frac{2 \sqrt{3} }{3} ) - 15 \sqrt{3} + 20 \sqrt{2}$

$12 \sqrt{12} - \frac{16 \sqrt{18} }{3} - 15 \sqrt{3} + 20 \sqrt{2}$

$24 \sqrt{3} - \frac{48 \sqrt{2} }{3} - 15 \sqrt{3} + 20 \sqrt{2}$

$24 \sqrt{3} - 16 \sqrt{2 } - 15 \sqrt{ 3} + 20 \sqrt{2}$

$9 \sqrt{3} + 4 \sqrt{2}$

Sper ca te-am ajutat