Question

Calculand (4x-3) la puerea a 2 a - (3x-2) la puterea a 2a + (2x+5) la puterea a 2a , obtinem rezultatul...
Vreau o explicatie

Answer 1

(4x-3)²-(3x-2)²+(2x+5)²=16x²-24x+9-9x²+12x-4+4x²+20x+25=11x²+8x+30

Answer 2

formula e a^2+2ab+b^2- cind e cu +
iar cind e cu - e asa a^2-2ab+b^2
(4-3x)^2=4^2-2*4*(-3)+(3x)^2=16+24x+9x^2
(3x-2)^2=(3x)^2-2*3x*(-2)+(-2)^2=9x^2+12x-4
(2x+5)^2=(2x)^2+2*2x*5+5^2=4x^2+20x+25
acum facem toate calculele care le-scris in conditie
16+24x+9x^2-9x^2+12x-4+4x^2+20x+25=37+56x+4x^2