Question

Calculați:
0,5: [1/3+1/3la puterea 2 -0,1 (6)].

Answer 1

$\frac{1}{2}: [\frac{1}{3} +\frac{1}{3}^2-0,1(6) ]$
$\frac{1}{2} :( \frac{1}{3}+ \frac{1}{9}- \frac{10}{90})= \frac{1}{2}:( \frac{3}{9}+ \frac{1}{9}- \frac{1}{9}) = \frac{1}{2}* \frac{9}{3}= \frac{3}{2}$