Question

calculati [1,1(6)+1intreg din 1 pe 4 : 0,(3)]immultit (2-4 pe 3)totul la a doua .

Answer 1

[ 1,1(6) + 1 1/4 : 0,(3)] × (2 - 4/3)^2 =

= [ (116-11)/90 + 5/4 : 3/9] × (6/3-4/3)^2 =

= ( 105/90 + 5/4 × 3) × (2/3)^2 =

= ( 21/18 + 15/4) × 4/9 =

= (7/6 + 15/4) × 4/9 =

= (14/12 + 45/12) × 4/9 =

= 59/12 × 4/9 =

= 59/27 =

= 2,1(851)