Question

Calculați: {(1/2)³+[(2/3-5/12)²+1/6-(93/90-39/45)]:3/2}×6

Answer 1

$\left(\frac{1}{2}\right)^3+\frac{\frac{\left(\frac{2}{3}-\frac{5}{12}\right)^2+1}{6-\left(\frac{93}{90}-\frac{39}{45}\right)}}{\frac{3}{2}\times \:6}=\frac{61}{420}$

$\left(\frac{1}{2}\right)^3=\frac{1}{2^3}$

$=\frac{1}{2^3}+\frac{17}{840}$

$=\frac{1}{8}+\frac{17}{840}$

$=\frac{105+17}{840}$

$=\frac{122}{840}$

$=\frac{61}{420}$

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