Question

calculati {1+[25-3×(12×4-43)]×5}×4 b) 6×{[(75-5×13)×5-43]×7+1}

Answer 1

{1+[25-3×(12×4-43)]×5}×4=204
={1+[25-3x(48-43)]x5}x4=
=[1+(25-3x5)x5]x4=
=[1+(25-15)x5]x4=
=(1+10x5)x4=
=51x4=
=204

 b)
 6×{[(75-5×13)×5-43]×7+1}=300
=6x{[(75-65)x5-43]x7+1}=
=6x[(10x5-43)x7+1]=
=6x(7x7+1)=
=6x50=
=300