Question

calculați :
1. 2⁵×(3⁴+4²-7²)=
2. 64:2²+3²×5²=
3. 7³+8²-5³=
4. 7×(3³+4³-2⁵)=
5. 64:(2⁴×2²:2³)=
(6 l am rezolvat in clasa)
7. 3×(4²-3²)+5×(6²-3³)
8. 3×(27+5²-49)
9. 36:(4²+7²-5²)⁰
​

Answer 1

Răspuns:

1) 32x(81+16-49)=

   32x(97-49)=

   32x48=1824

2) 16+9x25=

    16+225=

     241

3)343+64-75=

   407-75=

   332

4) 7x(27+64-25)=

   7x(91-25)=

   7x66=

    462

5) 64:(16x4:8)=

    64:8=

    8

7) 3x(16-9)+5x(36-27)=

  3x7+5x9=

  21+45=

   66

8) 3x(27+25-29)=

   3x23=

   69

9) 36:(4^2+7^2-5^2)^0=

   1

(orice nr ridicat la puterea 0 este egal cu 1)

 

Sper ca te-am ajutat :)

Answer 2

1. 2^5(3^4+4^2-7^2) =

32(81+16-49) =

32*48 =

1536

2. 64:2^2+3^2*5^3 =

2^6:2^2+9*125 =

2^4+1125 =

16+1125 =

1141

3. 7^3+8^2-5^3 =

343+64-125 =

282

4. 7(3^3+4^3-2^5) =

7(9+64-32)=

7*41 =

287

5. 64:(2^4*2^2:2^3) =

2^6:(2^4+2-3) =

2^6:2^3 =

2^3 =

8

7. 3(4^2-3^2)+5(6^2-3^3) =

3(16-19)+5(36-27) =

3*7+5*9 =

21+45 =

66

8. 3(27+5^2-49) =

3(27+25-49) =

3*3 =

9

9. 36:(4^2+7^2-5^2)^0 =

36:1 =           (orice expresie la puterea 0 este 1)

36