Question

Calculati: 1
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3-2√2

Answer 1

$\frac{1}{3 - 2 \sqrt{2} } = \frac{1(3 + 2 \sqrt{2}) }{(3 - 2 \sqrt{2}) \times (3 + 2 \sqrt{2}) } = \frac{3 + 2 \sqrt{2} }{9 - 4 \times 2} = \frac{3 + 2 \sqrt{2} }{9 - 8} = \frac{3 + 2 \sqrt{2} }{1} = 3 + 2 \sqrt{2}$