Question

Calculati :1) [(3/5)^7:(2-1 intreg 2/5)^4+5:1 intreg 1/4-(3/5)^3]: 1 intreg 3/5
2) [(1/2+2/3+5/6):12/7-6*1/18]*1/4:(5*12/25-1 intreg 1/3)
3) {2+2 intregi 1/2-2/3*[0,(1)+0,(2)]}:3,1(6)
4) {8/35+[(3/2-33/35)+(3/14-2/35)-(2-12/7+5-14)]}*3 intregi 1/3 Ajutati-ma va rog !! Urgent

Answer 1

1)
2-1 intreg 2/5=2-(5+2)/5=2-7/5=(2x5-7)/5=(10-7)/5=3/5
1 intreg 1/4=(1x4+1)/4=5/4
1 intreg 3/5=(1x5+3)/5=8/5
[(3/5)^7:(2-1 intreg 2/5)^4+5:1 intreg 1/4-(3/5)^3]: 1 intreg 3/5 =
=[(3/5)^7:(3/5)^4+5:(5/4)-(3/5)^3]:(8/5)=
=[(3/5)^7x(5/3)^4+5x(4/5)-(3/5)^3]:(8/5)=
=[(3/5)^3+4-(3/5)^3]:(8/5)=
=4:(8/5)=
=4x(5/8)=
=5/2=2intreg(1/2)

2. 
1/2+2/3+5/6=(1x3+2x2+5)/6=12/6
6*1/18=6/18=(6:3)/(18:3)=2/6
5*12/25=12/5
1 intreg 1/3=(1x3+1)/3=4/3
12/5-4/3=(12x3-4x5)/(5x3)=16/15

 [(1/2+2/3+5/6):12/7-6*1/18]*1/4:(5*12/25-1 intreg 1/3)=
=[(12/6)x(7/12)-(2/6)]*(1/4):(12/5-4/3)=
=[(7/6)-(2/6)]x(1/4):(16/15)
=(5/6)x(1/4)x(15/16)=
=75/384

3)
2 intregi 1/2=(2x2+1)/2=5/2
0,(1)=(1-0)/9=1/9
0,(2)=(2-0)/9=2/9
3,1(6)=(316-31)/90=285/90
(1/9)+(2/9)=3/9=1/3

{2+2 intregi 1/2-2/3*[0,(1)+0,(2)]}:3,1(6)=
={2+(5/2)-(2/3)x[(1/9)+(2/9)]}:(285/90)=
=[2+(5/2)-(2/3)x(1/3)]x(90/285)=
=[(2x2x9+5x9-2x2)/(2x9)]x(90/285)=
=(77/18)x(90/285)=
=77/57=1intreg 20/57

4)

3/2-33/35=(3x35-33x2)/(2x35)=39/70
3/14-2/35=(3x5-2x2)/(2x5x7)=11/70
2-12/7+5-14=(2x7-12+5x7-14x7)/7= -61/7
3 intregi 1/3=(3x3+1)/3=10/3
39/70+11/70-(- 61/7)=(39+11)/70+(61/7)=(50/70)+(61/7)=(5/7)+(61/7)=66/7

{8/35+[(3/2-33/35)+(3/14-2/35)-(2-12/7+5-14)]}*3 intregi 1/3=
={8/35+[39/70+11/70-(- 61/7)]}x(10/3)=
=(8/35+66/7)x(10/3)=
=[(8+66x5)/7]x(10/3)=
=(338/7)x(10/3)=
=3380/21=160intregi 20/21

SPER ca nu am gresit la calcule
am incercat sa adaug scanarea rezolvarii pe hartie, dar nu am reusit (prea multe caractere)