Question

Calculati:
1) 3 intregi 5/14-[ 1 intreg 11/49:(76x25/38-47 intregi 3/7)]x12/5=
2) {[(6 intregi 9/16-2 intregi 1/2-1 intreg 9/14)x0,53]:0,75}:6 intregi 2/3=

Answer 1

3 intregi 5/14=(3x14+5)/14=47/14
1intreg11/49=(1x49+11)/49=60/49
47intregi3/7=(47x7+3)/7=332/7
1) 3 intregi 5/14-[ 1 intreg 11/49:(76x25/38-47 intregi 3/7)]x12/5=
47/14-[60/49:(76x25/38-332/7)]x12/5=
47/14-[60/49:(50-332/7)]x12/5=
47/14-[60/49:(350/7-332/7)]x12/5=
47/14-[60/49:18/7]x12/5=
47/14-[60/49x7/18]x12/5=
47/14-10/21x12/5=
47/14-8/7=(47-8x2)/14=31/14=2,2(142857)

2) {[(6 intregi 9/16-2 intregi 1/2-1 intreg 9/14)x0,53]:0,75}:6 intregi 2/3=
{[(105/16-5/2-23/14)x53/100]:75/100}:20/3=
{[(105x7-5x56-23x8)/112x53/100]x100/75}x3/20=
{[(735-280-184)/112x53/100]x100/75}x3/20=
271/112x53/100x100/75x3/20=14363/56000=0,256482(142857)